Given the root of a binary tree, return the inorder traversal of its nodes' values.

Example 1:

Input: root = [1,null,2,3]
Output: [1,3,2]
Example 2:

Input: root = []
Output: []
Example 3:

Input: root = [1]
Output: [1]
Example 4:

Input: root = [1,2]
Output: [2,1]
Example 5:

Input: root = [1,null,2]
Output: [1,2]

Constraints:

The number of nodes in the tree is in the range [0, 100].
-100 <= Node.val <= 100

Follow up: Recursive solution is trivial, could you do it iteratively?